May 4, 2021
May 4, 2021

## EET272 Fiber Optics Communication

Complete and submit the following items found in your textbook. Show all your calculations and explain how you came up with that answer. Please highlight all your solutions with GREEN color. (Leave the RED for my comments).

Question-1. Calculate critical angle when n1 = 1.4290 and n2 = 1.4086.

Solution:

Refractive index within material=1.429

Refractive index outside material 1.4086

=80.31 deg

Question-2. What is na if n1 = 1.448 and n2 = 1.331

Solution:

C:UsersfredPicturesc21uf001.png

Question-3. Define the cone of acceptance core is 1.4432 and the cladding 1.370, n1 and n2 are the indices of refraction of the core and cladding, respectively.

Solution:

n2

a guided

guided

core

n1 guided

Acceptance Cone

Critical Modes

guided mode

The post Define the cone of acceptance core is 1.4432 and the cladding 1.370, n1 and n2 are the indices of refraction of the core and cladding, respectively. first appeared on Blackboard Masters.